Thread and shared lock

在看programing python 4th,第5张parallel system tool 192页开始,书中讲到thread知识,以下做个笔记,以便后期学习

1.主线程执行,开启5个子线程进行计数,没有使用mutex锁住,所以线程没有lock住资源,每个线程对全局变量的操作错乱,结果如下:

 1 """
 2 synchronize access to stdout: because it is shared global
 3 thread outputs may be intermixed if not syschronized
 4 """
 5 import thread,time
 6 global num                                  #global var to be used by many threads
 7 num=0
 8 
 9 def cnt(id,count):                          # function run in threads
10     for i in range(count):
11         global num
12         #mutex.acquire()                     # lock the share var before execute 
13         num +=1
14         time.sleep(0.5)                     # simulate read work
15         print('[%s] num= %s\n' %(id,num))   #print isn't interrupted now
16         #mutex.release()                     #release the lock for the other thread
17 
18 if __name__ =="__main__":
19     #mutex=thread.allocate_lock()            #make a global mutex for lock
20     for i in range(5):                      #spawm 5 threads
21         thread.start_new_thread(cnt,(i,3))  #start threads
22     time.sleep(8)                          # wait for spawn thread work done,don't exit too early
23    
24     print('main thread exitting')
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2.把mutex 注释打开,有了mutex变量,每一个线程进入都会独占num变量,结果如下:

 1 """
 2 synchronize access to stdout: because it is shared global
 3 thread outputs may be intermixed if not syschronized
 4 """
 5 import thread,time
 6 global num                                  #global var to be used by many threads
 7 num=0
 8 
 9 def cnt(id,count):                          # function run in threads
10     for i in range(count):
11         global num
12         mutex.acquire()                     # lock the share var before execute 
13         num +=1
14         time.sleep(0.5)                     # simulate read work
15         print('[%s] num= %s\n' %(id,num))   #print isn't interrupted now
16         mutex.release()                     #release the lock for the other thread
17 
18 if __name__ =="__main__":
19     mutex=thread.allocate_lock()            #make a global mutex for lock
20     for i in range(5):                      #spawm 5 threads
21         thread.start_new_thread(cnt,(i,3))  #start threads
22     time.sleep(8)                          # wait for spawn thread work done,don't exit too early
23    
24     print('main thread exitting')
View Code

3.如果把time.sleep(6)注释掉或者子线程没有执行完毕,而主线程sleep的时间一到,主线程直接退出而不等待子线程执行完毕,结果如下:

a.主线程不等待,则直接退出

b.主线程只等待3s,而5个子线程需要7.5s,所以num只计数5.

4.设定有效等待时间和锁之后,主线程等待所有子线程执行结束才退出,结果如下:

6.无需在主线程设置等待时间,而是设定单独的锁或者变量来记录每个子线程的执行状态,每执行完一个线程,设定状态锁,然后在主线程判断所有状态锁的状态即可

 1 """
 2 used mutexex to know when threads are done in parent/main thread,
 3 instead of time.sleep;lock stdout to avoid comingled prints
 4 """
 5 import thread,time
 6 global num   
 7 num =0
 8 
 9 def cnt(id,count):
10     for i in range(count):
11         global num
12         stdoutmutex.acquire()
13         num +=1
14         time.sleep(0.5)
15         print('[%s] num= %s time:[%s]\n' %(id,num,time.ctime()))   #print isn't interrupted now
16         stdoutmutex.release()
17     #exitmutexs[id].acquire() # signal main thread
18     exitFlags[id] = True     #signal main thread
19     
20 if __name__ =="__main__":           
21     stdoutmutex = thread.allocate_lock()                           #make a global mutex for lock
22     #exitmutexs = [thread.allocate_lock() for i in range(5)] 
23     exitFlags=[False]*5
24     for i in range(5):                                             #spawm 5 threads
25         thread.start_new_thread(cnt,(i,3))                         #start threads
26     #for mutex in exitmutexs:
27     #    while not mutex.locked():                                  
28     #        pass
29     while False in exitFlags:pass
30     print('main thread exitting')
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posted @ 2015-09-12 12:58  lxk613  阅读(223)  评论(0编辑  收藏  举报