摘要: TreeNode* mergeTrees(TreeNode* root1, TreeNode* root2) { if(root1==nullptr){ return root2; }else if(root2==nullptr){ return root1; } TreeNode* root=ne 阅读全文
posted @ 2022-09-07 10:19 lwx_R 阅读(26) 评论(0) 推荐(0)
摘要: Node* connect(Node* root) { if(root==NULL){ return root; } queue<Node*> q; q.push(root); while(!q.empty()){ int size=q.size(); for(int i=0;i<size;i++) 阅读全文
posted @ 2022-09-07 10:07 lwx_R 阅读(27) 评论(0) 推荐(0)