摘要: 5.1 def drawaq(n): line = 3n+1 for i in range(1,line+1): if i%3 == 1: print(n"+ ",end="") print("+") else: print("| "*n,end="") print("|") n = eval(in 阅读全文
posted @ 2025-04-20 19:15 渔樵伴夜归客 阅读(37) 评论(0) 推荐(0)