layui中的视频上传(PHP )

1.html中:

<div class="layui-form-item">
<label class="layui-form-label">视频:</label>
<div class="layui-input-inline">
     <!--存放上传后视频路径-->
        <input type="text" name="video"  id="inputvideourl" placeholder="视频地址" value="" class="layui-input"> 
</div>
  <!--视频显示代码-->
<video width="320" height="240" controls="controls" autoplay="autoplay">
<source id="show_video" src="{:isset($list.video)?$list.video:''}" type="video/mp4" />
</video>
<button type="button" class="layui-btn" id="upload_video"><i class="layui-icon"></i>上传视频</button>
</div>

2.js中:

//上传视频
upload.render({
elem: '#upload_video'
    ,url: "上传接口"
,accept: 'video' //视频
,done: function(res){
$("#inputvideourl").val(res.data.src);
layer.msg('上传成功');
}
});

3.上传接口:

public function upload()
{
$file = request()->file('file');
$info = $file->validate(['size'=>3145728])->move( '../public/uploads');
if($info){
$msg=['code'=>0,'msg'=>'上传成功','data'=>['src'=>'/uploads/'.str_replace('\\', '/', $info->getSaveName())]];
}else{
$msg=['code'=>1,'msg'=>$file->getError()];
}
return $msg;
}

样例截图:

 

 

 
posted @ 2020-04-20 17:26  北往星辰  阅读(2403)  评论(0编辑  收藏  举报