Just DO IT by luckygxf

摘要： The set[1,2,3,…,n]contains a total ofn! unique permutations.By listing and labeling all of the permutations in order,We get the following sequence (ie... 阅读全文

摘要： Given a list, rotate the list to the right bykplaces, wherekis non-negative.For example:Given1->2->3->4->5->NULLandk=2,return4->5->1->2->3->NULL.这道题有点... 阅读全文

摘要： Follow up for "Unique Paths":Now consider if some obstacles are added to the grids. How many unique paths would there be?An obstacle and empty space i... 阅读全文

摘要： A robot is located at the top-left corner of amxngrid (marked 'Start' in the diagram below).The robot can only move either down or right at any point ... 阅读全文

摘要： Given an integer, convert it to a roman numeral.Input is guaranteed to be within the range from 1 to 3999. 1 public class Solution { 2 public Stri... 阅读全文

摘要： Given a sorted array of integers, find the starting and ending position of a given target value.Your algorithm's runtime complexity must be in the ord... 阅读全文

摘要： Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.If such arrangement is not possibl... 阅读全文

摘要： 参考：http://www.cnblogs.com/springfor/p/3871008.htmlDivide two integers without using multiplication, division and mod operator.If it is overflow, retur... 阅读全文

摘要： java 整型int占4个字节32位，两个数异或后移动31位判断结果，如果是1则异号，如果是0则同号 1 public class ShowEnviromentViarible { 2 3 public static void main(String[] args) { 4 ... 阅读全文

摘要： 原出处：http://blog.csdn.net/yingfox/article/details/1831848一、基本概念位的概念：在计算机中，一个0或1称为一位(bit)。字节：连续的八位称为一个字节(Byte)，字节是计算机中可单独处理的最小单位。即以字节为基本单位来解释信息，规定1个字节是8... 阅读全文