摘要: task4 源码 //task4 #include<stdio.h> int main() { int i = 0; char ch; FILE *fp; fp = fopen("data4.txt", "r"); if(fp == NULL) { printf("读取失败\n"); return 阅读全文
posted @ 2023-06-09 12:43 南博图 阅读(26) 评论(0) 推荐(0)