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方法一: select product_id,product_name from ( select a.product_id,product_name, case when sale_date<='2019-03-31' and sale_date>='2019-01-01' then 0 else 阅读全文
posted @ 2021-06-27 21:30
luckie
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方法一:case when语句 select buyer_id from ( select buyer_id, case product_name when 'S8' then 0 else 1 end as r from Sales a left join Product b on a.produ 阅读全文
posted @ 2021-06-27 21:11
luckie
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方法一:dense_rank()结合group by一起使用 select seller_id from ( select seller_id, dense_rank() over (order by sum(price) desc) r from Sales group by seller_id 阅读全文
posted @ 2021-06-27 19:52
luckie
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