C#打开指定目录的文件夹

string path = @"C:\Program Files"
System.Diagnostics.Process.Start(
"explorer.exe", path);

===========打开当前程序的文件夹目录

            string path = Application.StartupPath;
            System.Diagnostics.Process.Start("explorer.exe", path);


posted @ 2011-12-16 22:20  秦小米  Views(916)  Comments(0Edit  收藏  举报