【SI152笔记】part3:整数规划
SI152: Numerical Optimization
Lec 7. Integer Programming, Cutting Plane, Branch and Bound
Integer Programming
can be solved using their LP relaxation:
An optimal z of (LP) is a lower bound for (IP).
Relaxations
(LP): just show lower bound
Basic idea: Find an optimal solution \(x^∗\) of some LP is feasible for IP.
The convex hull of the feasible integer solutions is defined as: \(\mathsf{conv}(S) = \mathsf{conv}\{x \in \mathbb{R}^n | Ax \leq b, x\in\mathbb{Z}^n\}.\)
In other words, it is the smallest convex set that contains all integer feasible points.
Cutting Planes
inequality denoted by (π, π0) is valid for a polyhedron \(\mathcal{P}\) if \(π^T x \leq π_0, \forall x\in\mathcal{P}\).
The Separation Problem: Given a polyhedron \(\mathcal{Q} \subset \mathbb{R}^n\) and \(x^* \in\mathbb{R}^n\), determine whether \(x^* \in\mathbb{R}^n\) and if not, determine \((π, π_0)\), a valid inequality for \(\mathcal{Q}\) such that \(π^T x^∗ > π_0\) (violated with \(x^*\)).
If \(a\leq b\) and \(a \in \mathbb{Z}\), then \(a\leq \lfloor b \rfloor\).
cutting plane 1
From that, we can find Chvátal-Gomory inequalities for \(\mathsf{conv}(\mathcal{S})\):
If \(\mathcal{P} = \{x|Ax \leq b\}\),
- multiply each row by an integer \(k_i > 0\) and sum them
- Take the floor of the right-hand side\[ Ax\leq b \longrightarrow \sum_i \lfloor k_i a^T_i \rfloor x \leq \left\lfloor \sum_i k_i b_i \right\rfloor \]
- we get a valid Chvátal-Gomory inequality for the integer problem.
cutting plane 2
After simplex method for LP, choose one based variable \(x_i\),
Then the cutting palne is \(\bar{b}_i - \lfloor \bar{b}_i \rfloor - \sum_j (\bar{y}_{i,j} - \lfloor \bar{y}_{i,j} \rfloor) x_j \leq 0\).
It's violated by the current vertex \(x\), since \(x_i + \sum_j \lfloor y_{i,j} \rfloor x_j - \lfloor \bar{b}_i \rfloor = \bar{b}_i - \lfloor \bar{b}_i \rfloor > 0\)
Cutting plane method
Shortly speaking: Pick fractional \(x_i\). Create cutting plane. Adding new slack variable \(s_k\) for inequality. Continue pivoting using dual simplex method.

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