如何使异步方法执行完之后再执行后面代码

 

  使用      return new Promise((resolve,reject)=>{    resolve(res) });

//这是异步方法 加前缀async 
async changeFileNo(){
        return new Promise((resolve,reject)=>{
          var fileNo =this.fileNoList.join(",");                      
          var    Id= this.authId;                             
          postAction('/file/fileUploadLog/authfileAdd?Id=' + Id + '&fileId=' + fileNo).then(res => {
            console.log("保存fileNo",res)
            this.$message.success(res.message); 
            resolve(res);         
          });
        })

       
      },

 

  

方法名前面加 await 前缀；

       

 httpAction(httpurl,this.model,method).then(async (res)=>{
              if(res.success){
                
                if(this.authAddFlag){
                  await this.changeFileNo();
                  that.$emit('ok');
                }else{
                  that.$message.success(res.message);
                  that.$emit('ok');
                }             
              }else{
                that.$message.warning(res.message);
              }
            })