题目的dfs函数与骑士🔗类似,所以去写了下
代码:
#include<bits/stdc++.h>
using namespace std;
const int N = 6e4 + 7;
int f[N][2], a[N], in[N];
int head[N], tot;
struct Edge{
int ne, to;
}e[N];
void addedge(int u, int v){
e[++ tot].ne = head[u];
e[tot].to = v;
head[u] = tot;
}
void dfs(int now){
f[now][0] = 0, f[now][1] = a[now];
for(int i = head[now]; i ;i = e[i].ne){
int to = e[i].to;
dfs(to);
f[now][0] += max(f[to][0], f[to][1]);
f[now][1] += f[to][0];
}
}
int main(){
int n;
scanf("%d", &n);
for(int i = 1;i <= n;i ++) scanf("%d", &a[i]);
for(int i = 1;i < n;i ++){
int l, k;
scanf("%d%d", &l, &k);
addedge(k, l);
in[l] ++;
}
int rt = 0;
for(int i = 1;i <= n;i ++)
if(in[i] == 0){
rt = i;
break;
}
dfs(rt);
printf("%d", max(f[rt][0], f[rt][1]));
return 0;
}