python - ajax - 提交表单
1. 静态页面
<div class="panel panel-default"> <div class="panel-heading"> 小案例 ajax学习之路 - jq 绑定事件 - 表单提交 </div> <div class="panel-body"> <form method="post" id="addform" novalidate> {% for field in form %} <div class="form-group"> <label for="exampleInputEmail1"> {{ field.label }}</label> {{ field }} <span style="color:red" class="error-msg"> </span> </div> {% endfor %} <button type="button" id="btnadd" class="btn btn-primary">提交</button> </form> </div> </div>
<script type="text/javascript">
$(function (){
bindBntaddEvent();
})
function bindBntaddEvent(){
$('#btnadd').click(function (){
$.ajax({
url: '/task/add/',
type: 'post',
// 获取表单中的所有数据
data:$('#addform').serialize(),
dataType:'JSON',
success:function (res){
$('.error-msg').empty();
if (res.status){
alert('添加成功');
//js刷新页面
location.reload();
} else{
//console.log(res.error)
// 拿到错误数据 循环出来 键值对
$.each(res.error, function (name, data){
// 显示 需要的 name 与 data
//console.log(name, data)
// 拼接字符转id_title
$('#id_' + name).next().text(data[0]);
})
}
}
})
})
}
</script>
2. views.py 代码
from django.shortcuts import render, HttpResponse, redirect
# 免除认证 发送消息
from django.views.decorators.csrf import csrf_exempt
from app import models
from app.utils.bootsrap import BootstrapModelForm
# 返回json
from django.http import JsonResponse
'''为接受数据创建一个 modelform ''' class TaskModelForm(BootstrapModelForm): class Meta: model =models.task fields = '__all__' ''' ajax 表单 提交''' @csrf_exempt def task_add(request): # 数据校验 form = TaskModelForm(request.POST) if form.is_valid(): # 验证成功 form.save() data_dict = {'status': True} return JsonResponse(data_dict) # 验证失败 data_dict = {'status': False, 'error': form.errors} return JsonResponse(data_dict)