/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int> >res;//记录结果
void dfs(TreeNode *root,int sum,vector<int> temp){//temp记录每一条可能的路径
if(!root) return;
if(!root->left&&!root->right&&sum == root->val){//满足条件
temp.push_back(sum);
res.push_back(temp);
}
temp.push_back(root->val);
dfs(root->left,sum-root->val,temp);
dfs(root->right,sum-root->val,temp);
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<int>temp;
dfs(root,sum,temp);
return res;
}
};