A+B Problem的一些离谱解法

代码均为C++

1.正解

#include<iostream>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    cout<<a+b<<endl;
    return 0;
}

2.差点TLE

#include <bits/stdc++.h>
using namespace std;
int main() {
    int a, b;
    if (!(cin >> a >> b)) return 0;
    volatile int x = 0;
    for (int i = 0; i < 5e7; ++i) x += i * 0;
    cout << a + b << '\n';
    return 0;
}

3.差点MLE

#include <bits/stdc++.h>
using namespace std;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int a, b;
    if (!(cin >> a >> b)) return 0;
    constexpr size_t n = (1 << 20) - 64;
    vector<char> v(n);
    for (size_t i = 0; i < n; ++i) v[i] = char(i);
    cout << a + b << '\n';
    return 0;
}

4.它CE了？假的！

#include <bits/stdc++.h>
using namespace std;

int main() {
    int a, b;
    if (!(cin >> a >> b)) return 0;
    vector<int> v(1 << 20);
    cout << a + b << '\n';
    return 0;
}

5.这代码可太长了

#include <bits/stdc++.h>
using namespace std;

namespace APlusB {

template<typename T>
struct TypeTrait {
    static constexpr const char* name = "unknown";
};

template<>
struct TypeTrait<int> {
    static constexpr const char* name = "int";
};

template<>
struct TypeTrait<long long> {
    static constexpr const char* name = "long long";
};

template<typename T>
struct Input {
    static T read() {
        T x;
        std::cin >> x;
        return x;
    }
};

template<typename T>
T add(T a, T b) {
    return a + b;
}

struct Validator {
    template<typename T>
    static bool inRange(T) { return true; }
};

template<typename T>
struct Output {
    static void write(T x) {
        std::cout << x << '\n';
    }
};

template<typename T>
struct Solver {
    void solve() {
        T a = Input<T>::read();
        T b = Input<T>::read();
        if (!Validator::inRange(a) || !Validator::inRange(b)) return;
        T c = add(a, b);
        Output<T>::write(c);
    }
};

}  // namespace APlusB

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    APlusB::Solver<int> solver;
    solver.solve();
    return 0;
}

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