单片机处理串口逗号分隔符命令

串口接收回调函数如下:

/**
  * @brief  Rx Transfer completed callbacks.
  * @param  huart pointer to a UART_HandleTypeDef structure that contains
  *                the configuration information for the specified UART module.
  * @retval None
  */
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *huart)
{    
  /* Prevent unused argument(s) compilation warning */
  UNUSED(huart);
  /* NOTE: This function Should not be modified, when the callback is needed,
           the HAL_UART_TxCpltCallback could be implemented in the user file
   */ 
    if(huart->Instance == huart1.Instance)
    { 
        if(bRx1_complete != 0)
            return;//接收的命令还没处理完,不再接收新数据
        
        if(Uart1_Rx_Cnt >= 255)  //溢出判断
        {
            Uart1_Rx_Cnt = 0;
            memset(Uart1_RxBuff,0x00,sizeof(Uart1_RxBuff));    
        }
        else
        {
            Uart1_RxBuff[Uart1_Rx_Cnt] = aRx1Buffer;   //接收数据转存
            Uart1_Rx_Cnt++;
            if((Uart1_RxBuff[Uart1_Rx_Cnt-1] == 0x0A)&&(Uart1_RxBuff[Uart1_Rx_Cnt-2] == 0x0D)) //判断结束位(回车换行符)
            {                     
                Uart1_Rx_Cnt= 0;
                bRx1_complete = 1;//接收完成            
            }
        }    
    } 
    HAL_UART_Receive_IT(&huart1, (uint8_t *)&aRx1Buffer, 1);   //再开启接收中断
}

解析每个逗号前的字符

        if(bRx1_complete == 1)
        {
            char *ptr,*retptr;
            int i=0;
            ptr = Uart1_RxBuff;//指针指向串口1接收的缓冲数组
            while ((retptr=strtok(ptr, ",")) != NULL) {//逐个解析逗号前的字符
                printf("substr[%d]:%s\r\n", i++, retptr);//打印每个逗号前的字符
                switch(i)
                {
                    case 1:SavePara(retptr,ppara1);break;//保存第1个字符
                    case 2:SavePara(retptr,ppara2);break;
                    case 3:SavePara(retptr,ppara3);break;
                    case 4:SavePara(retptr,ppara4);break;
                    case 5:SavePara(retptr,ppara5);break;
                    case 6:SavePara(retptr,ppara6);break;//保存第6个字符
                    default:
                        break;
                }
                ptr = NULL;
            }
      }

 

posted @ 2019-09-17 10:26  阿坦  阅读(736)  评论(0编辑  收藏  举报