摘要: if (RandomUtil.randomInt(10) > 2){ // 1.高频}else if (RandomUtil.randomInt(10) > 3){ // 2} else if (RandomUtil.nextBoolean()){}int result = RandomUtil.randomInt(3);switch (result){ case 0: ... 阅读全文
posted @ 2018-12-04 21:55 lizb0907 阅读(204) 评论(0) 推荐(0)