160-13. 罗马数字转整数

给定一个罗马数字,转为整数(都是我写的,我很开心,如果我不思考这个问题看起来很难,但是当我思考了他就变得不是那么难)
class Solution(object):
    data_dict = {"I": 1, "V": 5, "X": 10, "L": 50, "C": 100, "D": 500, "M": 1000}

    def get_value(self, symbol):
        """-1表示出问题了"""
        return self.data_dict.get(symbol, -1)

    def romanToInt1(self, s):
        """
        :type s: str
        :rtype: int
        """
        if len(s) < 2:
            return self.get_value(s) if self.get_value(s) != -1 else 0

        i = 0
        count = 0
        while i < len(s):
            cur_value = self.get_value(s[i])
            next_value = self.get_value(s[i + 1])
            if cur_value == -1:
                return count

            if cur_value >= next_value:
                count += cur_value
                i += 1
            else:
                count += next_value - cur_value
                i += 2

            if i + 1 == len(s):
                count += self.get_value(s[i])
                break

        return count

    def romanToInt(self, s):
        """
        :type s: str
        :rtype: int
        """
        i = 0
        count = 0
        while i < len(s):
            if i < len(s) - 1:
                cur_value = self.get_value(s[i])
                next_value = self.get_value(s[i + 1])
                if cur_value == -1:
                    return count

                if cur_value >= next_value:
                    count += cur_value
                else:
                    count -= cur_value
            else:
                count += self.get_value(s[i])
            i += 1
        return count


if __name__ == '__main__':
    s1 = Solution()
    s = "D"
    print(s1.romanToInt(s))