摘要:
计算 2Λ(n-1) < v <2Λ(n-1)uint32_t RoundUpPow2(uint32_t v) { v--; v |= v >> 1; v |= v >> 2; v |= v >> 4; v |= v >> 8; v |= v >> 16; return v+1;}判断是否是2的n次幂bool IsPowerOf2(int v) { return (v & (v - 1)) == 0;} 阅读全文
posted @ 2012-04-17 10:27
littlepearl
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