摘要: 题解: #include<stdio.h>#include<math.h>int main(){ int n; scanf("%d",&n); int a[20000]={0}; int i,j; for(i=4;i<20000;i+=2){ a[i]=1; } for(i=3;i<sqrt(200 阅读全文
posted @ 2020-02-01 11:23 BlueValentines 阅读(158) 评论(0) 推荐(0)