摘要: awk '/SUCCESS/ {if (NR > 1) print ""; printf "%s", $0; next} /^[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+/ {printf " | %s", $0; next} END {print ""}' ljs-ip202503 阅读全文
posted @ 2025-03-27 09:48 LB_运维技术 阅读(16) 评论(0) 推荐(0)