青春叛逆者

摘要： li=[[1,2,3],[2,3,4],[3,4,5],[4,5,6]] xx=[[y*y for y in i] for i in li] aa=[y*y for i in li for y in i] print(aa)#[1, 4, 9, 4, 9, 16, 9, 16, 25, 16, 25, 36] print(xx)#[[1, 4, 9], [4, 9, 16], [9, 16, ... 阅读全文