python成长之旅6

函数闭包补充：解压序列
一、
        l = [10,19,2,3,5,90]
        a,*_,c = l
        a        #此处为dos环境中回车，后面雷同
        10
        c
        90
    运用序列一一对应关系    
    etc:    a,b,c = (1,2,3)
            a 
            1
            b 
            2
            c 
            3
    etc:    a,b,c = 'hel'
            a
            'h'
            b
            'e'
            c
            'l'
            
        数值交换
            a = 1
            b = 2
            a,b = b,a #将a,b值已经交换
            
            
        
        
装饰器作业：
        def auth_func(func):
            def wrapper(*args,**kwargs):
                username = input('用户名：')
                password = input('密码：')
                
            if username == 'alex' and password == '1234':
                res = func(*args,**kwargs)
                return res
                
            else:
                print('用户名或者密码错误')
                
        return wrapper
        
        @auth_func(func)
        
        def index(name):
                print('fastly hello jindon!')
        @auth_func(func)        
        def shopping_car(name):
                print('%s的购物车里面有[%s,%s]',%(name,'xiezi',''wazi))