摘要:
#include int main(){ double x = 12.5; printf("%d\n",x); int y = 10; printf("%lf\n",y);} 输出: 0 0.000000 float x = 12.5; printf("%d\n", x);flo... 阅读全文
摘要:
Can you find it? Time Limit: 10000/3000 MS (Java/Others) Memory Limit: 32768/10000 K (Java/Others) Total Submission(s): 6083 Accepted Submiss... 阅读全文