PY_RE(py字典)

题目：
start.py

import Test

Dict = {}
key = "A"
value = 26
for i in range(1, 27):
    Dict.setdefault(key, value)
    print(Dict)
    key = chr(ord(key) + 1)
    value = value - 1
print("===================Py_Reverse====================")


def main():
    Input_Str = input("Please Input Str:\n")
    Input_Str = list(Input_Str)
    print(Input_Str)
    Test.EnData1(Input_Str, Dict)

    Test.Judge(Input_Str)


main()

test.py

def EnData1(Input_Str, Dict):
    for i in range(int(len(Input_Str) / 2), len(Input_Str)):
        for dict in Dict:
            if Input_Str[i] == str(dict):
                Input_Str[i] = Dict[dict]
                # print(Input_Str)
                break


def Judge(Input_Str):
    FLAG = ["H", "E", "L", "L", "O", "_", "_", 11, 2, 7, 19, 12, 13]
    if str(Input_Str) == str(FLAG):
        print(str(Input_Str))
        print(str(FLAG))
        print("YES!")
    else:
        print(str(Input_Str))
        print(str(FLAG))
        print("NO!")


all_data = []


def EnData(Input_Str, Dict):
    for i in range(int(len(Input_Str) / 2), len(Input_Str)):
        flag = 0
        for dict in Dict:
            if Input_Str[i] == dict:
                all_data.append(Dict[dict])
                flag = 1
        if flag == 0:
            all_data.append(Input_Str[i])

思路：
分析EnData1，发现他把输入的数据的后半部分和字典的键作比较，并将对应的键的值赋予后半部分
类似于

所以根据FLAG = ["H", "E", "L", "L", "O", "", "", 11, 2, 7, 19, 12, 13]，只需找到后面数字对于的键
HELLO__PYTHON