摘要: 链接:https://atcoder.jp/contests/abc466 A - Compromise 涉及知识:无 思路:判断有无非负数即可 Code 点击查看代码 void solve() { cin >> n; vi a(n + 1); int ok = 0; for (int i = 1; 阅读全文
posted @ 2026-07-23 17:55 Lambda_L 阅读(2) 评论(0) 推荐(0)