摘要: import os import zipfile def zip_path(filepaths): ''' 压缩文件 :param filepaths: 压缩文件源目录 :return: ''' for file in filepaths: zip = zipfile.ZipFile("{}.zip 阅读全文
posted @ 2022-09-01 13:53 knva 阅读(535) 评论(0) 推荐(0) 编辑