05 2020 档案

xctf easyre
摘要：一道简单的题目 while ( v1 < 24 ); v4 = 0; do { byte_40336C[v4] = (byte_40336C[v4] + 1) ^ 6;// 关键处理加一异或6 ++v4; } while ( v4 < 0x18 ); v5 = strcmp(byte_40336C, 阅读全文
posted @ 2020-05-26 11:49 kailicard 阅读(343) 评论(0) 推荐(0)