坤丶

摘要： # lambda 函数from functools import reducea = lambda x: x ** 2print(a(3))def power(func, l=[]): return [func(x) for x in l]print(power(lambda x: x ** 2, 阅读全文

摘要： # 闭包def my_power(): n = 2 def power(x): return x ** n return power# n=3 输出依旧是16power = my_power()print(power(4))print(power.__closure__) #(<cell at 0x 阅读全文