摘要: 统计每个人的总成绩排名 select stu.`name`,sum(stu.score) as totalscore from stu GROUP BY `name` order by totalscore 统计每门课程的总分排序 SELECT stu.class, sum(stu.score) a 阅读全文
posted @ 2021-05-07 16:48 KinoLogic 阅读(296) 评论(0) 推荐(0)