摘要:
统计每个人的总成绩排名 select stu.`name`,sum(stu.score) as totalscore from stu GROUP BY `name` order by totalscore 统计每门课程的总分排序 SELECT stu.class, sum(stu.score) a 阅读全文
posted @ 2021-05-07 16:48
KinoLogic
阅读(296)
评论(0)
推荐(0)
浙公网安备 33010602011771号