摘要:
Problem A Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 463 Accepted Submission(s): 162 Problem 阅读全文
摘要:
#include using namespace std; const int N = 1e6+5; char a[N]; int main() { scanf("%s",a+1); int n = strlen(a+1); int l = 1,r = n; while(l = 0 && a[r] == '0') r--; ... 阅读全文
摘要:
#include #include using namespace std; long long a[50005]; long long sum[50005]; int main() { int n; cin>>n; for(int i=1;i>a[i]; sum[i]=sum[i-1]+a[i];... 阅读全文