实验7，，= =

最近开始学习汇编咯～，，下面是王爽的《汇编语言（第二版）》中实验7的解决方案

PS：这本书大赞啊，，，很通俗易懂

assume cs:codesg,ss:stacksg

data segment
    db '1975','1976','1977','1978','1979','1980','1981','1982','1983'

    db '1984','1985','1986','1987','1988','1989','1990','1991','1992'

    db '1993','1994','1995'

    dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514

    dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

    dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226

    dw 11452,14430,15257,17800


data ends

table segment
	db 21 dup ('year summ ne ?? ')
table ends

stacksg segment
	db 8 dup(0)
stacksg ends

codesg segment
start:	mov ax,data
	mov ds,ax
	mov ax,table
	mov es,ax
	mov ax,stacksg
	mov ss,ax
	mov sp,8

	mov cx,21
	mov bx,0
	mov bp,0

s1:	push cx
	
	;copy year
	mov cx,4
	mov si,0
s2:	mov al,[bx+si]
	mov es:[bp+si],al
	inc si
	loop s2

	;copy summ
	mov cx,4
	mov si,0
s3:	mov al,[bx+si+84]
	mov es:[bp+si+5],al
	inc si
	loop s3
	
	;copy ne
	mov cx,2
	mov si,0
s4:	mov al,[bx+si+168]
	mov es:[bp+si+10],al
	inc si
	loop s4

	
	add bx,4
	add bp,16	
	pop cx
	loop s1

	mov ax,4c00h
	int 21h
codesg ends

end start