摘要: (a + b) % mod = ((a % mod) + (b % mod)) % mod; (a * b) % mod = ((a % mod) * (b % mod)) % mod; (a - b) % mod = ((a % mod) - (b % mod) + mod) % mod; // 阅读全文
posted @ 2025-06-03 10:32 光風霽月 阅读(9) 评论(0) 推荐(0)