摘要: const array1 = [1, 2, 3, 4]; // 0 + 1 + 2 + 3 + 4 const initialValue = 0; const sumWithInitial = array1.reduce( (accumulator, currentValue, currentInd 阅读全文
posted @ 2025-02-27 09:37 sky-su 阅读(7) 评论(0) 推荐(0)