package LeetCode_153
/**
* 153. Find Minimum in Rotated Sorted Array
https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).
Return the minimum element of this array.
Example 1:
Input: nums = [3,4,5,1,2]
Output: 1
Example 2:
Input: nums = [4,5,6,7,0,1,2]
Output: 0
Example 3:
Input: nums = [1]
Output: 1
Constraints:
1. 1 <= nums.length <= 5000
2. -5000 <= nums[i] <= 5000
3. All the integers of nums are unique.
4. nums is sorted and rotated at some pivot
* */
class Solution {
/*
* solution: Divide and conquer, check left side and right side of array,
* Time complexity: O(logn), Space complexity: O(logn) (there are logn levels recursion)
* */
fun findMin(nums: IntArray): Int {
return findMin(nums, 0, nums.size - 1)
}
private fun findMin(nums: IntArray, left: Int, right: Int): Int {
//is sorted
if (nums[left] <= nums[right]) {
return nums[left]
}
//compare left and right side
val mid = left + (right - left) / 2
val leftSide = findMin(nums, left, mid)
val rightSide = findMin(nums, mid+1, right)
return Math.min(leftSide, rightSide)
}
}