package LeetCode_282
/**
* 282. Expression Add Operators
* https://leetcode.com/problems/expression-add-operators/description/
*
* Given a string that contains only digits 0-9 and a target value, return all possibilities to add binary operators (not unary) +, -, or * between the digits so they evaluate to the target value.
Example 1:
Input: num = "123", target = 6
Output: ["1+2+3", "1*2*3"]
Constraints:
0 <= num.length <= 10
num only contain digits.
* */
class Solution {
private val result = ArrayList<String>()
private var num = ""
private var target = 0L
/**
* solution: dfs, Time complexity:O(4^n), Space complexity:O(n)
* */
fun addOperators(num: String, target: Int): List<String> {
this.num = num
this.target = target.toLong()
dfs(0, "", 0, 0)
return result
}
private fun dfs(index: Int, candidate: String, curSum: Long, last: Long) {
if (target == curSum && index == num.length) {
result.add(candidate)
return
}
for (i in index until num.length) {
if (i != index && num[index] == '0') {
break//avoid "01"
}
val next = num.substring(index, i + 1).toLong()
if (index == 0) {
//the first must be +
dfs(i + 1, next.toString(), next, next)
continue
}
dfs(i + 1, candidate + "+" + next, curSum + next, next)
dfs(i + 1, candidate + "-" + next, curSum - next, -next)
dfs(i + 1, candidate + "*" + next, curSum - last + last * next, last * next)
}
}
}