package LeetCode_236
/**
* 236. Lowest Common Ancestor of a Binary Tree
* https://leetcode.com/problems/lowest-common-ancestor-of-a-binary-tree/description/
* https://www.geeksforgeeks.org/lowest-common-ancestor-binary-tree-set-1/
* */
class TreeNode(var `val`: Int = 0) {
var left: TreeNode? = null
var right: TreeNode? = null
}
class Solution {
fun lowestCommonAncestor(root: TreeNode?, p: TreeNode?, q: TreeNode?): TreeNode? {
if (root==null){
return null
}
if (root.`val` == p?.`val` || root.`val` == q?.`val`) {
return root
}
val left = lowestCommonAncestor(root?.left, p, q)
val right = lowestCommonAncestor(root?.right, p, q)
// If both of the above calls return Non-NULL, then one key
// is present in once subtree and other is present in other,
// So this node is the LCA
if (left != null && right != null) {
return root
}
if (left != null) {
return left
} else {
return right
}
}
}