摘要:
1.委托的定义internal delegate int MyAddFunDe(int a,int b)2.匿名方法1)MyAddFunDe fun = delegate(int a,int b){ return a+b;}2)lambdaMyAddFunDe fun = (int a,int b) =>{ return a+b;}3)简洁版MyAddFunDe fun = (a,b) => a+b; 阅读全文
posted @ 2014-01-27 15:12
守恪
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