算法函数：得到一个字符串中的最大长度的数字

 /**//// <summary>
        /// 获取字符串最长的数字
        /// </summary>
        /// <param name="inputStr">输入字符串</param>
        /// <returns>最长数字</returns>
        public string GetMaxLenNumber(string inputStr)
        {
            //将字符串中的字符存放到数组中，便于处理
            char[] strCharArray = inputStr.ToCharArray();
            //开始处理的位置
            int startPos = 0;
            //当前处理的字符长度
            int tempCharCount = 0;
            //数字的最长长度
            int maxLen = 0;
            //数组的总长度
            int len = strCharArray.Length;
            int pos = 0;
            while (startPos < len)
            {
                //循环中的临时最大长度
                int tempMax = 0;
                while (tempCharCount + startPos < len)
                {
                    //开始处理的字符
                    char c = strCharArray[tempCharCount + startPos];
                    if (char.IsNumber(c))
                    {
                        //如果是数字
                        tempMax++;
                        if (tempMax > maxLen)
                        {
                            maxLen = tempMax;
                            pos = startPos;
                        }                       
                    }
                    else
                    {
                        //不是数字
                        tempMax = 0;
                        startPos++;
                        break;
                    }
                    tempCharCount++;
                }
                if (startPos + tempCharCount == len)
                {
                    break;
                }
                tempCharCount = 0;             
            }
            string s = inputStr.Substring(pos, maxLen);
            return s;
        }