一、实验内容

task1-1

#include<stdio.h>
#define N 4

int main()
{
	int a[N] = { 2,0,2,2 };
	char b[N] = { '2','0','2','2' };
	int i;

	printf("sizeof(int)=%d\n", sizeof(int));
	printf("sizeof(char)=%d\n", sizeof(char));
	printf("\n");

	for (i = 0; i < N; ++i)
		printf("%p:%d\n", &a[i], a[i]);

	printf("\n");

	for (i = 0; i < N; ++i)
		printf("%p:%c\n", &b[i], b[i]);

	printf("\n");

	printf("a=%p\n", a);
	printf("b=%p\n", b);

	return 0;
}

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问题①

int型数组a在内存中连续存放,每个元素占用4个内存字节单元;

问题②

char型数组b在内存中连续存放,每个元素占用1个内存字节单元;

问题③

数组名a对应的值和&a[0]是一样的,数组名b对应的值和&b[0]是一样的。

task1-2

#include<stdio.h>
#define N 2
#define M 3

int main()
{
	int a[N][M] = { {1,2,3},{4,5,6} };
	char b[N][M] = { {'1','2','3'},{'4','5','6'} };
	int i, j;

	for (i = 0; i < N; ++i)
		for (j = 0; j < M; ++j)
			printf("%p:%d\n", &a[i][j], a[i][j]);

	printf("\n");

	for (i = 0; i < N; ++i)
		for (j = 0; j < M; ++j)
			printf("%p:%c\n", &b[i][j], b[i][j]);

	return 0;

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问题①

int型二维数组a在内存中按行连续存放,每个元素占用4个内存字节单元;

问题②

char型二维数组b在内存中按行连续存放的,每个元素占用1个内存字节单元。

task2

#include<stdio.h>

int days_of_year(int year, int month, int day);

int main()
{
	int year, month, day;
	int days;

	while (scanf_s("%d%d%d", &year, &month, &day) != 0)
	{
		days = days_of_year(year, month, day);
		printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);
	}

	return 0;
}

#define N 13
int days_of_year(int year, int month, int day)
{
	int a[N] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
	int days=0,i;

	if (year % 400 == 0 || year % 4 == 0 && year % 100 != 0)
		a[0] = day, a[2] = 29;
	else a[0] = day;

	for (i = 0; i < month; i++)
		days+= a[i];

	return days;
}

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task3

#include<stdio.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void sort(int x[], int n);

int main()
{
	int scores[N];
	double ave;

	printf("录入%d个分数:\n", N);
	input(scores, N);

	printf("\n输入课程分数:\n");
	output(scores, N);

	printf("\n课程分数处理:计算均分、排序...\n");
	ave = average(scores, N);
	sort(scores, N);

	printf("\n输出课程均分:%.2f\n", ave);
	printf("\n输出课程分数(高->低):\n");
	output(scores, N);

	return 0;
}

void input(int x[], int n)
{
	int i;

	for (i = 0; i < n; ++i)
		scanf_s("%d", &x[i]);
}

void output(int x[], int n)
{
	int i;

	for (i = 0; i < n; ++i)
		printf("%d ", x[i]);

	printf("\n");
}

double average(int x[], int n)
{
	int sum = 0, i;
	double ave;

	for (i = 0; i < n; ++i)
	{
		sum += x[i];
	}
	ave = 1.0*sum / N;
	return ave;
}

void sort(int x[], int n)
{
	int i, j, temp;
	for (i = 1; i < n; i++)
	{
		for (j = 0; j < n-1; j++)
		{
			if (x[j] < x[j + 1])
			{
				temp = x[j];
				x[j] = x[j + 1];
				x[j + 1] = temp;
			}
		}
	}
}

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task4

#include<stdio.h>
void dec2n(int x, int n);

int main()
{
	int x;

	printf("输入一个十进制整数:");
	scanf_s("%d", &x);

	dec2n(x, 2);
	dec2n(x, 8);
	dec2n(x, 16);

	return 0;
}

void dec2n(int x, int n)
{
	if (x == 0)
		printf("\n");
	else
		{
			dec2n(x / n, n);

			if (n >= 10)
			{
				if (x % n >= 10)
				printf("%c\n", (char)((x % n - 10) + 'A'));
				else
				printf("%d", x % n);
			}
			else
			printf("%d", x % n);
	}
}

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task5

#include<stdio.h>
#define N 100

int main()
{
	int n, i, j, x[N][N];
	printf("Enter n:");
	while (scanf_s("%d", &n) != 0)
	{
		for (i = 0; i <= n - 1; i++)
		{
			for (j = 0; j <= n - 1; j++)
			{
				if (i <= j)
					x[i][j] = i + 1;
				else
					x[i][j] = j + 1;
					printf("%2d", x[i][j]);
			}
			printf("\n");
		}
		printf("\nEnter n:");
	}
	return 0;
}

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task6

#include<stdio.h>
void output(char x[]);
void sort(char x[], char y[]);
#define N 80

int main()
{
	char views1[N] = "hey,c,i hate u.";
	char views2[N] = "hey,c,i love u.";

	printf("original views:");

	printf("\nviews1:");
	output(views1);
	printf("\nviews2:");
	output(views2);

	printf("\n\nswapping...\n");

	sort(views1, views2);

	printf("\nviews1:");
	output(views1);
	printf("\nviews2:");
	output(views2);

	return 0;
}

void output(char x[])
{
	for (int i=0; x[i] != '\0'; i++)
		printf("%c", x[i]);
}

void sort(char x[], char y[])
{
	int temp;
	for (int i = 0; x[i] != '\0'; i++)
	{
		temp = x[i];
		x[i] = y[i];
		y[i] = temp;
	}
}

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task7

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>

#define N 5
#define M 20
void bubble_sort(char str[][M], int n);
int main()
{
	char name[][M] = { "Bob","Bill","Joseph","Taylor","George" };
	int i;

	printf("输出初始名单:\n");
	for (i = 0; i < N; i++)
		printf("%s\n", name[i]);

	printf("\n排序中...\n");
	bubble_sort(name, N);

	printf("\n按字典序输出名单:\n");
	for (i = 0; i < N; i++)
		printf("%s\n", name[i]);

	return 0;
}

void bubble_sort(char str[][M], int n)
{
	char temp[M];
	for (int i = 0; i < n - 1; i++)
	{
		for (int j = 0; j < n - 1; j++)
		{
			if (strcmp(str[j], str[j + 1]) > 0)
			{
				strcpy(temp, str[j]);
				strcpy(str[j], str[j + 1]);
				strcpy(str[j + 1], temp);
			}
		}
	}
}

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Posted on 2022-05-08 13:01  llllllimit  阅读(15)  评论(2编辑  收藏  举报