摘要: var formData = new FormData(); for (var i = 0; i < $("#files")[0].files.length; i++) { formData.append("file", $("#files")[0].files[i]); } $.ajax({ type: "post", url: '', data: formData, ... 阅读全文
posted @ 2019-09-18 18:46 介寒食 阅读(421) 评论(0) 推荐(0) 编辑