上下箭头切换开关 

<body>
<div class="arr">
    <img src="arr-down.png" alt="">
</div>
<script src="js/jquery.js"></script>
<script>
    var $arr = $('.arr');
    var target = false;
    $arr.click(function () {
        target = !target;
        if (target) {
            $arr.find('img').attr('src', 'arr-up.png');
        } else {
            $arr.find('img').attr('src', 'arr-down.png');
        }
    });
</script>
</body>

　　

posted @ 2017-08-17 21:55  透明的月儿  阅读(374)  评论(0)    收藏  举报