C语言100个算法经典例题(六)

【程序51】
题目:学习使用按位与 & 。
1.程序分析:0&0=0; 0&1=0; 1&0=0; 1&1=1

程序源代码:
#include "stdio.h"
main()
{
int a,b;
a
=077;
b
=a&3;
printf(
"\40: The a & b(decimal) is %d \n",b);
b
&=7;
printf(
"\40: The a & b(decimal) is %d \n",b);
}

==============================================================
【程序52】题目:学习使用按位或 | 。
1.程序分析:0|0=0; 0|1=1; 1|0=1; 1|1=1

程序源代码:
#include "stdio.h"
main()
{
int a,b;
a
=077;
b
=a|3;
printf(
"\40: The a & b(decimal) is %d \n",b);
b
|=7;
printf(
"\40: The a & b(decimal) is %d \n",b);
}

==============================================================
【程序53】题目:学习使用按位异或 ^ 。
1.程序分析:0^0=0; 0^1=1; 1^0=1; 1^1=0

程序源代码:
#include "stdio.h"
main()
{
int a,b;
a
=077;
b
=a^3;
printf(
"\40: The a & b(decimal) is %d \n",b);
b
^=7;
printf(
"\40: The a & b(decimal) is %d \n",b);
}

==============================================================
【程序54】题目:取一个整数a 从右端开始的4~7 位。
程序分析:可以这样考虑:
(1)先使a右移4位。
(2)设置一个低4位全为1,其余全为0的数。可用~(~0<<4)
(3)将上面二者进行&运算。

程序源代码:
main()
{
unsigned a,b,c,d;
scanf(
"%o",&a);
b
=a>>4;
c
=~(~0<<4);
d
=b&c;
printf(
"%o\n%o\n",a,d);
}

==============================================================
【程序55】题目:学习使用按位取反~。
1.程序分析:~0=1; ~1=0;

程序源代码:
#include "stdio.h"
main()
{
int a,b;
a
=234;
b
=~a;
printf(
"\40: The a's 1 complement(decimal) is %d \n",b);
a
=~a;
printf(
"\40: The a's 1 complement(hexidecimal) is %x \n",a);
}

==============================================================
【程序56】题目:画图,学用circle 画圆形。
1.程序分析:

程序源代码:
/*circle*/
#include
"graphics.h"
main()
{
int driver,mode,i;
float j=1,k=1;
driver
=VGA;mode=VGAHI;
initgraph(
&driver,&mode,"");
setbkcolor(YELLOW);
for(i=0;i<=25;i++)
{
setcolor(
8);
circle(
310,250,k);
k
=k+j;
j
=j+0.3;
}
}

==============================================================
【程序57】题目:画图,学用line 画直线。27
1.程序分析:

程序源代码:
#include "graphics.h"
main()
{
int driver,mode,i;
float x0,y0,y1,x1;
float j=12,k;
driver
=VGA;mode=VGAHI;
initgraph(
&driver,&mode,"");
setbkcolor(GREEN);
x0
=263;y0=263;y1=275;x1=275;
for(i=0;i<=18;i++)
{
setcolor(
5);
line(x0,y0,x0,y1);
x0
=x0-5;
y0
=y0-5;
x1
=x1+5;
y1
=y1+5;
j
=j+10;
}
x0
=263;y1=275;y0=263;
for(i=0;i<=20;i++)
{
setcolor(
5);
line(x0,y0,x0,y1);
x0
=x0+5;
y0
=y0+5;
y1
=y1-5;
}
}

==============================================================
【程序58】题目:画图,学用rectangle 画方形。
1.程序分析:利用for循环控制100-999个数,每个数分解出个位,十位,百位。

程序源代码:
#include "graphics.h"
main()
{
int x0,y0,y1,x1,driver,mode,i;
driver
=VGA;mode=VGAHI;
initgraph(
&driver,&mode,"");
setbkcolor(YELLOW);
x0
=263;y0=263;y1=275;x1=275;
for(i=0;i<=18;i++)
{
setcolor(
1);
rectangle(x0,y0,x1,y1);
x0
=x0-5;
y0
=y0-5;
x1
=x1+5;
y1
=y1+5;
}
settextstyle(DEFAULT_FONT,HORIZ_DIR,
2);
outtextxy(
150,40,"How beautiful it is!");
line(
130,60,480,60);
setcolor(
2);
circle(
269,269,137);
}

==============================================================
【程序59】题目:画图,综合例子。
1.程序分析:

程序源代码:
# define PAI 3.1415926
# define B
0.809
# include
"graphics.h"
#include
"math.h"
main()
{
int i,j,k,x0,y0,x,y,driver,mode;
float a;
driver
=CGA;mode=CGAC0;
initgraph(
&driver,&mode,"");
setcolor(
3);
setbkcolor(GREEN);
x0
=150;y0=100;
circle(x0,y0,
10);
circle(x0,y0,
20);
circle(x0,y0,
50);
for(i=0;i<16;i++)
{
a
=(2*PAI/16)*i;
x
=ceil(x0+48*cos(a));
y
=ceil(y0+48*sin(a)*B);
setcolor(
2); line(x0,y0,x,y);}
setcolor(
3);circle(x0,y0,60);
/* Make 0 time normal size letters */
settextstyle(DEFAULT_FONT,HORIZ_DIR,
0);
outtextxy(
10,170,"press a key");
getch();
setfillstyle(HATCH_FILL,YELLOW);
floodfill(
202,100,WHITE);
getch();
for(k=0;k<=500;k++)
{
setcolor(
3);
for(i=0;i<=16;i++)
{
a
=(2*PAI/16)*i+(2*PAI/180)*k;
x
=ceil(x0+48*cos(a));
y
=ceil(y0+48+sin(a)*B);
setcolor(
2); line(x0,y0,x,y);
}
for(j=1;j<=50;j++)
{
a
=(2*PAI/16)*i+(2*PAI/180)*k-1;
x
=ceil(x0+48*cos(a));
y
=ceil(y0+48*sin(a)*B);
line(x0,y0,x,y);
}
}
restorecrtmode();
}

==============================================================
【程序60】题目:画图,综合例子。
1.程序分析:

程序源代码:
#include "graphics.h"
#define LEFT 0
#define TOP 0
#define RIGHT 639
#define BOTTOM 479
#define LINES 400
#define MAXCOLOR 15
main()
{
int driver,mode,error;
int x1,y1;
int x2,y2;
int dx1,dy1,dx2,dy2,i=1;
int count=0;
int color=0;
driver
=VGA;
mode
=VGAHI;
initgraph(
&driver,&mode,"");
x1
=x2=y1=y2=10;
dx1
=dy1=2;
dx2
=dy2=3;
while(!kbhit())
{
line(x1,y1,x2,y2);
x1
+=dx1;y1+=dy1;
x2
+=dx2;y2+dy2;
if(x1<=LEFT||x1>=RIGHT)
dx1
=-dx1;
if(y1<=TOP||y1>=BOTTOM)
dy1
=-dy1;
if(x2<=LEFT||x2>=RIGHT)
dx2
=-dx2;
if(y2<=TOP||y2>=BOTTOM)
dy2
=-dy2;
if(++count>LINES)
{
setcolor(color);
color
=(color>=MAXCOLOR)?0:++color;
}
}
closegraph();
}
posted @ 2011-08-22 12:09  心灵工程师  阅读(357)  评论(0编辑  收藏  举报