摘要:
#includevoid main(){int m,n,i,test,sum,count;printf("Input:\n");scanf("%d",&n);count=0;sum=0;for(i=0;i=60)count++;}printf("avr=%.2f\n",sum*1.0/n);printf("pass=%d\n",count);printf("fail=%d\n",n-count);} 阅读全文
posted @ 2013-10-19 22:32
1850年老街
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