摘要:
#includeint main(void){ int m,n,i; double y; y=1; printf("Enter m,n:"); scanf("%d%d",&m,&n); for(i=m;i<=n;i++){ y=y+(i*i+1/i); } printf("y=%.2f",y); return 0;} 阅读全文
posted @ 2013-10-20 21:54
1850年老街
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