实验2

任务1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 5
#define N1 80
#define N2 35
int main()
{
int cnt;
int random_major, random_no;
srand(time(NULL));
cnt = 0;
while (cnt < N) {
random_major = rand() % 2;
if (random_major) {
random_no = rand() % N1 + 1;
printf("20256343%04d\n", random_no);
}
else {
random_no = rand() % N2 + 1;
printf("20256136%04d\n", random_no);
}
cnt++;
}
return 0;
}

屏幕截图 2025-10-19 185047

任务2

#include <stdio.h>

int main() {
int choice, quantity;
float total_price = 0, amount_paid, change;
while (1) {
printf("\n自动饮料售卖机菜单:\n");
printf("1. 可乐 - 3 元/瓶\n");
printf("2. 雪碧 - 3 元/瓶\n");
printf("3. 橙汁 - 5 元/瓶\n");
printf("4. 矿泉水 - 2 元/瓶\n");
printf("0. 退出购买流程\n");
printf("请输入饮料编号: ");
scanf_s("%d", &choice);
if (choice == 0)
break;
if (choice < 1 || choice > 4) {
printf("无效的饮料编号,请重新输入。\n");
continue;
}
printf("请输入购买的数量: ");
scanf_s("%d", &quantity);
if (quantity < 0) {
printf("购买数量不能为负数,请重新输入。\n");
continue;
}
if (choice == 1 || choice == 2)
total_price += 3 * quantity;
else if (choice == 3)
total_price += 5 * quantity;
else
total_price += 2 * quantity;
printf("请投入金额: ");
scanf_s("%f", &amount_paid);
change = amount_paid - total_price;
printf("本次购买总价: %.2f 元\n", total_price);
printf("找零: %.2f 元\n", change);
}
printf("感谢您的购买,欢迎下次光临!\n");
return 0;
}

屏幕截图 2025-10-20 055100
第一次总价还在

任务3

#include<stdio.h>
int main()
{
char color;
while (scanf_s("%c", &color) != EOF) {
if (color == '\n') {
continue;
}
else if (color == 'r') {
printf("stop!\n");
}
else if (color == 'g') {
printf("go go go\n");
}

	else if (color == 'y') {
		printf("wait a minute\n");
	}
	else {
		printf("something must be wrong...");
	}
}
return 0;

}

image

任务4

#include<stdio.h>
int main(){
double expense;
double sum=0.0;
double max=0.0,min=20000.0;
int count=0;
printf("请输入今日开销,直到输入-1终止:\n");
while(1){
scanf_s("%lf",&expense);
if(expense==-1)
{
break;
}
if(expense>0&&expense<=20000){
count=1;
sum+=expense;

if(expense>max){
max=expense;
}
if(expense<min){
min=expense;
}

}

}
if(count){
printf("今日累计消费总额:%.1lf\n",sum);
printf("今日最高一笔开销:%.1lf\n",max);
printf("今日最低一笔开销:%.1lf\n",min);
}
return 0;
}

屏幕截图 2025-10-20 060632
任务5
#include <stdio.h>
int main()
{
double a, b, c;
while(~scanf_s("%lf%lf%lf", &a, &b, &c)){

if(a+b>c&&a+c>b&&b+c>a){
if(aa+bbcc||bb+c*caa||aa+cc==bb)
printf("直角三角形\n");
else if(ab&&bc){
printf("等边三角形\n");
}
else if(ab||ac||c==b) {
printf("等腰三角形\n");
}

else printf("普通三角形\n");
}

else
printf("不能构成三角形\n");
}
return 0;
}

屏幕截图 2025-10-20 061200
任务6
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

define N 29

int main() {
int day, cnt = 0;
int inportant;

srand(time(NULL));
inportant = rand() % N + 1;

printf("猜猜2025年十一月那一天是你的lucky day\n");
printf("开始喽,你有三次机会,猜吧(1~30):");
while (cnt < 3) {
	scanf_s("%d", &day);
	if (day < inportant) {
		printf("你猜的日期早了,你的lucky day还没到呢\n");
		printf("再猜(1~30):");
	}
	else if (day > inportant) {
		printf("你猜的日期晚了,你的lucky day在前面呢\n");
		printf("再猜(1~30):");
	}

	else if (day = inportant) {
		printf("哇,猜中了\n");
		break;
	}

	cnt++;
}

if (cnt == 3)
	printf("次数用完啦,偷偷告诉你,11月你的lucky day是%d号", inportant);

return 0;

}

屏幕截图 2025-10-20 061628

posted @ 2025-10-20 06:18  蒋志凌  阅读(0)  评论(0)    收藏  举报