作业1

作业1

include <stdio.h>

include <stdlib.h>

int main()
{
printf(" o \n");
printf("\n");
printf("I I\n");
printf(" o \n");
printf("\n");
printf("I I\n");

system("pause");

return 0;

}

include<stdio.h>

int main(void){
printf(" O \t");
printf(" O \n");
printf("\t");
printf("\n");
printf("I I\t");
printf("I I\n");
return 0;
}

作业2

include <stdio.h>

int main()
{
double a, b, c;
while (scanf_s("%lf%lf%lf", &a, &b, &c) != EOF)
{
if (a + b > c && a + c > b && b + c > a)
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
}

return 0;

}

作业3

include <stdio.h>

int main()
{
int n = 4;
while (n--)

{   
    char ans1, ans2; 
    printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) : ");
    ans1 = getchar(); 
    getchar(); 
    printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) : ");
    ans2 = getchar();
    if (ans1 == 'y'&& ans2 == 'y' || ans1 == 'Y' && ans2 == 'Y') 
    {
        printf("\n罗马不是一天建成的, 继续保持哦:)\n");
        getchar();
    }
    else 
    {
        printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
        getchar();
    }
}
return 0;

}

作业4

include<stdio.h>

int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;
scanf("%d%d%d",&a1,&a2, &a3);
printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
scanf("%c%c%c", &c1, &c2, &c3);
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
scanf("%lf,%lf", &x, &y);
printf("x = %f, y = %lf\n",x, y);
return 0;
}

作业5

include <stdio.h>

include <math.h>

int main() {
int year;
long long seconds = 1000000000LL;
double result = seconds / 60.0 / 60 / 24 / 365;

year = round(result);
printf("10亿秒约等于%d年\n", year);

return 0;

}

作业6

include <stdio.h>

include <math.h>

int main()
{
double x, ans;
while (scanf_s("%lf", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}
return 0;
}

作业7

include <stdio.h>

include <math.h>

int main()
{
double c, f;
while (scanf_s("%lf", &c) != EOF)
{
f = 9.0 * c / 5.0 + 32;
printf("摄氏温度c= %.2f 时，华氏度f = %.2f\n", c, f);
printf("\n");
}
return 0;
}

作业8

include <stdio.h>

include <math.h>

int main()
{
int a, b, c;
while (scanf_s("%d %d %d", &a, &b, &c) != EOF) {
double s, area;
s = (a + b + c) / 2.0;
area = sqrt(s * (s - a) * (s - b) * (s - c));
printf("a = %d,b = %d,c = %d,area = %.3lf\n", a, b, c, area);
}
return 0;
}