随笔分类 -  几何

gym 101081 E. Polish Fortress 几何
摘要：E. Polish Fortress time limit per test 2.0 s memory limit per test 256 MB input standard input output standard output E. Polish Fortress time limit pe 阅读全文
posted @ 2017-09-13 14:36 jhz033 阅读(191) 评论(0) 推荐(0)
hdu 5120 Intersection 两个圆的面积交
摘要：Intersection Time Limit: 4000/4000 MS (Java/Others) Memory Limit: 512000/512000 K (Java/Others) Problem Description Matt is a big fan of logo design. 阅读全文
posted @ 2017-08-29 17:45 jhz033 阅读(196) 评论(0) 推荐(0)
hdu 2108 Shape of HDU 判断是否为凸多边形
摘要：Shape of HDU Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description 话说上回讲到海东集团推选老总的事情，最终的结果是XHD以微弱优势当选，从 阅读全文
posted @ 2017-08-25 15:19 jhz033 阅读(210) 评论(0) 推荐(0)
hdu 2034 改革春风吹满地 多边形面积
摘要：改革春风吹满地 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description “ 改革春风吹满地,不会AC没关系;实在不行回老家，还有一亩三分地。谢谢!（乐队奏 阅读全文
posted @ 2017-08-25 15:15 jhz033 阅读(227) 评论(0) 推荐(0)
hdu 1115 Lifting the Stone 多边形的重心
摘要：Lifting the Stone Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description There are many secret openings 阅读全文
posted @ 2017-08-25 14:34 jhz033 阅读(158) 评论(0) 推荐(0)
计算几何模板
摘要：%%%% orz 邝斌的计算几何模板： void change(double &x0,double &y0,double a,double b,double p)//x0,y0绕a，b旋转P度{ double x = a + (x0 - a) * cos(p) - (y0 - b) * sin(p) 阅读全文
posted @ 2017-04-10 11:12 jhz033 阅读(166) 评论(0) 推荐(0)