摘要:
import timefor i in range(0,101,2): time.sleep(0.1) char_num = i//2 per_st = '\r%s%%:%s\n'%(i,'*'* char_num) if i ==100 else '\r%s%%:%s'%(i,'*'*char_n 阅读全文
摘要:
30以内能够整除3的平方 ret = [i**2 for i in range(30) if i%3 ==0] print(ret) #找到嵌套列表中名字含有两个或两个以上e的所以名字names =[['jeera''bxhjbdw''eeeee','ceshi'],['emoe','shezhou 阅读全文