摘要:
The key to this problem is to store the values in a stack. In the constructor and next, we add all the next smallest nodes into the stack. The followi... 阅读全文
posted @ 2015-07-08 14:20
jianchao-li
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摘要:
The following idea is taken from a book named 《剑指offer》 published in China.Supposen = 271, it then breaks[1, 271]into[1, 71]and[72, 271]. For[72, 271]... 阅读全文
posted @ 2015-07-08 01:50
jianchao-li
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