PAT B1041 考试座位号(15)

解题要点:

  1. 使用结构体保存准考证号,考试座位号
  2. 试机座位号作考生数组下标
  3. 通过试机座位号获取考生号,座位号
  4. 考生号使用long long存放
//课本AC代码
#include <cstdio>
const int maxn = 1010;
struct Student {
	long long id;
	int examSeat;
} testSeat[maxn];
int main() {
	int n, m, seat, examSeat;
	long long id;
	scanf("%d", &n);
	for(int i = 0; i < n; i++) {
		scanf("%lld %d %d", &id, &seat, &examSeat);
		testSeat[seat].id = id;
		testSeat[seat].examSeat = examSeat;
	}
	scanf("%d", &m);
	for(int i = 0; i < m; i++) {
		scanf("%d", &seat);
		printf("%lld %d\n", testSeat[seat].id, testSeat[seat].examSeat);
	}
	return 0;
}

自己的WA代码

#include <cstdio>

const int max_n = 1010;

struct Stu {
	long long no;	//准考证号
	int seat_num;
	int test_num;
} stu[max_n];

int main() {
	#ifdef ONLINE_JUDGE
    #else
        freopen("1.txt", "r", stdin);
    #endif // ONLINE_JUDGE
    long long id;
    int seat, examSeat;
	int testSeat = 0;
	int n1 = 0, n2 = 0;
	scanf("%d", &n1);	//输入n个考生信息
	for(int i = 0; i < n1; i++) {
		scanf("%lld %d %d", &id, &seat, &examSeat);
		stu[i].no = id;
		stu[i].seat_num = seat;
		stu[i].test_num = examSeat;
	}
	scanf("%d", &n2);	//输入n个查询信息
	/*for(int i = 0; i < n1; i++) {
		printf("%lld %d %d\n ", stu[i].no, stu[i].seat_num, stu[i].test_num);
	}
	for(int i = 0; i < n2; i++) {
	}*/
	//误人子弟写法, 复杂度变高了不止, 还wa
	for(int i = 0; i < n2; i++) {
		scanf("%d", &testSeat);
		for(int j = 0; j < n1; j++) {
			if(testSeat == stu[j].test_num) {
				printf("%lld %d\n", stu[i].no, stu[i].test_num);
			}
		}
	}

	return 0;
}
posted @ 2019-07-26 18:04  哨音  阅读(214)  评论(0编辑  收藏  举报